If n is an integer greater than 0, what is the remainder when 9^12n+3 is divided by 10?
(A) 0
(B) 1
(C) 2
(D) 7
(E) 9

• ans is (E)9
• 14 years agoHelpfull: Yes(2) No(2)
• For any n, 912n is even and hence 912+3 is odd. When n=2, (912n+3) mod 10 = 7. When n=3, (912n+3) mod 10 = 9. When n=4, (912n+3) mod 10 = 1. So, n can be 1, 7 or 9. In fact, result can be any odd number.
• 14 years agoHelpfull: Yes(1) No(2)
• Ans : 4
  (10 -1)^12%10=1,
  therefore 1+3=4
  4 is the remainder
  
• 8 years agoHelpfull: Yes(1) No(0)