the great mathamatican names bhaskaracharya formulated this problem twelth century for his teenaged prime number aged lilavati.he also authoredd the eponymous lilavati ,a compendeum mathamtican puzzels ,in which no of problems that use this formula is sum of two prime numbers .the product of two prime numbers is smaller than the total of problems in lilavati .now,the difference of two numbers is 4 and their product is 18 .what is the sum of their squares?
options
a) 34
b) 40
c) 52
d) 42
e) none

• a^2+b^2=(a-b)^2+2ab=16+2*18=52
  Ans. 52
• 11 years agoHelpfull: Yes(31) No(0)
• as in question given data is:
  ab=18
  a-b=4
  now we put above value in eqn
  a^2+b^2=(a-b)^2+2ab
  = (4)^2+2.18=16+36=52 ans
  
• 11 years agoHelpfull: Yes(4) No(0)
• (a-b)^2=a^2+b^2-2ab
  a^2+b^2=2ab=2*18=36
• 11 years agoHelpfull: Yes(0) No(5)
• two numberz are 5 and 1 bcoz no numbers wil satisfy the 1st condition except there is 1 in the number i.e product less than sum
  so answeR is 26
• 11 years agoHelpfull: Yes(0) No(3)
• a^2 +b^2 +(2*18)=88
  a^2 +b^2=52
• 11 years agoHelpfull: Yes(0) No(0)
• why the hell have wasted time??
• 11 years agoHelpfull: Yes(0) No(0)