a schoolyad contains only bicyles and 4 wheels wagons .on tuesday total no of wheels in the schoolyard was 90.what could be the possille no of bycyles? explanation.
option
a) 12
b) 14
c) 10
d) 11

• ans 11
  I solved it through hit and trial,
  
  if there are 12 bicycles, then there are 24 wheels,
  remaining wheels= 90-24= 66%4(wheels of a car)= we get remainder as 2. (rejected)
  
  if there are 14 bicycles, then there are 28 wheels,
  remaining wheels= 90-28= 62%4(wheels of a car)= we get remainder as 2. (rejected)
  
  if there are 10 bicycles, then there are 20 wheels,
  remaining wheels= 90-20= 70%4(wheels of a car)= we get remainder as 2. (rejected)
  
  if there are 11 bicycles, then there are 22 wheels,
  remaining wheels= 90-22= 68%4(wheels of a car)= we get remainder as 0. (accepted)
• 11 years agoHelpfull: Yes(38) No(0)
• possible no.is 11 (11*2+17*4)
• 11 years agoHelpfull: Yes(8) No(2)
• by trial...
  11 bicycles and 17 wagons
  total =(11*2)+(17*4)=22+68=90
  so ans: d) option
• 11 years agoHelpfull: Yes(7) No(0)
• 2x+4y=90.
  only for x=11 among given options the equation holds good.
• 11 years agoHelpfull: Yes(5) No(0)
• 11*2+17*4
  11 is ansr
• 11 years agoHelpfull: Yes(4) No(0)
• ans=d>11 11*2=22
  90-22=68/4=17
• 11 years agoHelpfull: Yes(0) No(0)