determine the distance b/w x-intercept and z- intercept of equation is 2x+9y-3z=18.
option
a) 6.32
b) 10.82
c) 3
d) 5

• to find x intercept put y=0 and z=0. we get x=9. This can be written as (9,0,0)
  to find z intercept put x=0 and y=0. we get z=-6. This can be written as (0,0,-6)
  nw find d distance btwn these 2 points.. i.e sqrt((x2-x1)^2 + (y2-y1)^2 + (z2-z1)^2)...sqrt[ 9^2 + 0 + (-6)^2 ]=sqrt 117 = 10.8166 ~ 10.82
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• ans-10.82
  
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