1234124341234.......400 digits when divided by 909 leaves remainder??

• 123400%909=5230
  5230%909=685
  685 might be the remainder
  
• 11 years agoHelpfull: Yes(14) No(8)
• 400th digit will be 4
  399th digit will be 3
  398th digit will be 2
  397th digit will be 1
  909=9*101
  123412341234.....1234
  the series consists of 100-1's,100-2's,100-3's,100-4's
  sum=1000
  1000/9=remainder will be 1
  ans= 1/101 remainder =1
  
• 11 years agoHelpfull: Yes(12) No(12)
• Didnt get the solution!!! can any one explain it clearly ??
• 11 years agoHelpfull: Yes(8) No(3)
• Veerapuraju Pavan Ajay, i think ur solutn is wrong bcoz i don't think that there is any need to calculate the sum. Bcoz its a no only.......1234123412341234...........
• 11 years agoHelpfull: Yes(3) No(0)
• Taking 1st 4 digits
  1234/909 and the remainder is 325
  
  now 12341234/909 = remainder 650 = 2*325
  
  so for 400/4 digits = remainder = 100*325 =32500/909=685
  so, 685 is the answer
  
• 9 years agoHelpfull: Yes(2) No(0)
• i can't this solution tel me clearly one more time.
  
• 11 years agoHelpfull: Yes(0) No(3)