((34^31))^301 divided by 9 what is the remainder

• I think the answer is "7"
• 11 years agoHelpfull: Yes(4) No(3)
• 7
  34/9 gives remainder 7
  (7^3)/9 gives remainder 1
  (((7^3)^3110)/9*7/9)=1*7=7
  
• 11 years agoHelpfull: Yes(4) No(3)
• Ans:6
  M I correct..??
  
• 11 years agoHelpfull: Yes(2) No(11)
• ans : 7
  ((a)^m)^n= a^(m*n)
  ((34)^31)^301=34^(31*301) we get 34^9331 /9
  ((9*3)+7)=34
  ((9*3)+7)^9331 /9
  7^9331 /9
  
  7^1 % 9= 7
  7^2 % 9= 4
  7^3 % 9= 1
  the cycle form
  so divide the number 9331 by 3 it gives the remainder 1
  so the answer of 7^1 %9 =7
  the answer is 7
  
  
• 10 years agoHelpfull: Yes(2) No(1)
• 7 is the ans
• 11 years agoHelpfull: Yes(1) No(2)
• 31^301=last digit must be 1
  so 34^1/7
  ans 6
• 11 years agoHelpfull: Yes(0) No(5)
• (34^31)^301=34^9331
  34/9 gives 7 as reminder
• 11 years agoHelpfull: Yes(0) No(2)
• REMAINDER IS 7.
  31^301 'S UNIT DIGIT IS 1
  SO REMAINDER OF 34^1 / 9 IS 7.
• 11 years agoHelpfull: Yes(0) No(1)
• The remainder is 7.
• 11 years agoHelpfull: Yes(0) No(0)