A pizza shop made pizzas with many flavors. There are 10
different flavors, in that 7 flavors are taken to make pizza.
In how many ways they can arrange?

• 10c7=(10*9*8*7*6*5*4)/7!
  =120 ways
• 13 years agoHelpfull: Yes(24) No(2)
• ans.is 10P2=90
  BECOZ,we know, incase of arrange we follow,permutation
  and in case of select we follow combination..
  since in this question they mention arrenge so, we should follow permutation
• 13 years agoHelpfull: Yes(13) No(6)
• 7 flavours can be choosen out of 10 flavours in 10c7 ways.
  10c7=10!/7!*(10-7)!
  =10*9*8*7!/7!*3*2*1
  =120 ways
• 13 years agoHelpfull: Yes(11) No(4)
• NpM......here we call tat no of possible arrangement not collection so we use permutation rule....
• 12 years agoHelpfull: Yes(8) No(2)
• 10C7..dt vil be equal to 120..
• 13 years agoHelpfull: Yes(7) No(2)
• since we have to selec 7 flavours from 10 diff flavours so no of ways= 10c7=120
• 13 years agoHelpfull: Yes(4) No(1)
• total no of flavors = 10
  taken flavors = 7
  as per combination formula :nCr = n!/((n-r)!*r!)
  no of combinations are = 10!/((10-7)!*7!)
  = (10*9*8*7!)/(3!*7!)
  = 120 ways
  
  
• 12 years agoHelpfull: Yes(4) No(1)
• 10c7 =!10/(!7*!3)=120 ways
• 12 years agoHelpfull: Yes(3) No(0)