there is a cask of full of milk . E letter are drawn from the cask it is then filled with water .this process is repeted now the ratio of milk and to water in the cask is 16:9 what is the capacity of cask in the liter..?

• 5E
  
  if x is capacity of cask, then
  initially
  x ltr milk .. 0 ltr water
  after first draw and water filling by E ltrs,
  x-E ltr milk and E ltr water
  
  after 2nd draw and water filling by E ltrs,
  x- [2E-(E^2/x)] and 2E -( E^2)/x ltr water
  
  As per condition
  
  x- [2E-(E^2/x)] /[ 2E -( E^2)/x] = 16/9
  
  solving, we get
  x=5E
• 11 years agoHelpfull: Yes(13) No(0)
• {(x-e)/x}^2=16/25
  x=5e......answer
• 11 years agoHelpfull: Yes(2) No(1)
• let total milk = XE ltrs
  milk removed frm cask = X-E ltrs
  let water added = E ltrs
  since the process is repeated;
  milk removed =(X-2)E
  WATER ADDED = 2E
  TOTAL RATIO = (X-2)E/2E=16/9
  = X=50/9
• 11 years agoHelpfull: Yes(1) No(5)
• Let cask capacity =XE liters
  E liters are dawn from the cask it is then filled with water,
  this is two times=XE-2E
  Now total (X-2)E lits milk and 2E lits in the cask
  Then Ratio of milk and water=(X-2)E/2E=16/9
  Then X=50/9
  Then the capacity of cask=(50/9)E liters
• 11 years agoHelpfull: Yes(0) No(6)
• dude its litre not letter :/
• 11 years agoHelpfull: Yes(0) No(0)