A person starts multiplying consecutive positive integers from 20. How many numbers should he multiply before the will have result that will end with 3 zeroes?

• 5
  when next no. i.e 25 is to be multiplied we get 3 zeros.so the feasiblible no is obtained when multiplied from 20to24
• 9 years agoHelpfull: Yes(3) No(3)
• 20 yields a zero, 22*24*25 yields 2 more zeroes. So 6 is the answer
• 8 years agoHelpfull: Yes(3) No(2)
• 20 * 21 * 22 * 23 * 24 * 25
  20 * 21 * 22 * 23 * 24 * (5 * 5)
  20 * 21 * 22 * 5 * 23 * 24 * 5
  (even number multiplied with 5 yields zero that is 22 * 5 yields one zero and 24 * 5 yields another zero,there is already a zero in 20 ).Hence the number from 20 to 25 has to be multiplied to obtain 3 zeros.the answer is 6.
• 5 years agoHelpfull: Yes(0) No(0)