Find the smallest number that has exactly 36 factors.

• (a+1)(b+1)(c+1)=36
  
  so 4*3*3=36 Then the values of a,b,c= 3,2,2
  
  2^3 *3^2 * 5^2 = 1800
  
• 8 years agoHelpfull: Yes(0) No(0)
• prime factor of 36 is 2,2,3,3
  (a+1)(b+1)(c+1)(d+1)=36
  then value of a=2,b=2,c=1,d=1
  for smallest number=2^2*3^2*5^1*7^1=1260
• 8 years agoHelpfull: Yes(0) No(0)