ABC
*DEF
-----------
BFAE
DGFEG
ABCGG
----------
CHGFE
----------
A,B,C,D,E,F,G,H represent distinct integer from 0-9.and C+E=8.find
4A+3F+2B=?
AB+CD+EF+GH=?

• A=1
  B=2
  C=3
  D=4
  E=5
  F=6
  G=7
  H=8
  given as C+E=8
  which follow the above given conditions
  so 4A+3F+2B=4*1+3*6+2*2=26
  similiarly
  AB+CD+EF+GH=100
  AB
• 13 years agoHelpfull: Yes(2) No(7)
• THE MULTIPLICATION ACTUALLY IS:
  
  ABC
  *DEF
  ------
  BFAE
  DGFEG
  ABCGG
  ------------
  CHGFE
  
  THAT MEANS G=0 FIRST OF ALL. AND D=1 BCOZ D*ABC=ABC
  NOW,C+E=8 SO IT COULD BE 2,6 OR 6,2 OR 3,5 OR 5,3.(C CANT BE 0,1,7,8,9 AND 4 OTHERWISE E WILL ASLO BE 4)
  F*C AND C*E BOTH RESULTS LAST DIGIT AS E. IN THIS CASE CANT BE 2 COZ THEN E WILL BE 6 AND 2*6 =12 LAST DIGIT 2.LETS CHECK FOR C=3 THEN E WILL BE 5.3*5=15
  LAST DIGIT IS 5.ONE CONDITION IS FULFILLED.F*3 SHOULD RESULT IN LAST DIGIT AS 5.FOR THAT F WILL HAVE TO BE 5 ONLY WHICH IS NOT POSSIBLE AS E=5.
  SAME CONDITION FOR C=5.FINALLY U GET C=6,THEN E=2.F*6 SHOULD RESULT IN LAST DIGIT 2.F HAS TO BE 7.
  FROM THE MULTIPLICATION U CAN SEE THAT A+E=F THAT MEANS A=5.SO NOW IT BECOMES
  
  5B6
  *127
  --------
  B752
  10720
  5B600
  ----------
  6H072
  
  WITH VERY LITTLE TRIAL AND ERROR U CAN GET B=3 AND H=8.SO U HAVE
  A=5,B=3,C=6,D=1,E=2.F=7,G=0 ANG H=8.
  PUTTING THESE VALUES IN THE EQUN
  4A+3F+2B=47
  
  AB+CD+EF+GH=35
• 13 years agoHelpfull: Yes(0) No(0)