A company's selection process is described below:Applicant-1:Accepted
Applicant-2:Rejected
Applicant-3:Accepted
Applicant-4:Rejected
Applicant-5:Rejected Applicant-6:Accepted
Applicant-7:Rejected
Applicant-8:Rejected
Applicant-9:Rejected
Applicant-10:Accepted

and so on

If the acceptance percentage is 5%. Then find the number of applicants who applied and the number of accepted candidates

• If 1 student got selected, then 1 rejected
  If 2 students got selected, then 1+2 rejected
  If 3 students got selected, then 1+2+3 rejected
  If 4 students got selected, then 1+2+3+4 rejected
  If n students got selected, then (1+2+3+4+...+n) rejected =n(n+1)/2 rejected
  
  For n students to be selected, total students appeared is = students who got accepted + students who got rejected = n+n(n+1)/2
  
  acceptance percentage, n/[n+n(n+1)/2]=5
  solving it for n, we got n=37
  Therefore accepted students are, n=37
  total students are, n+n(n+1)/2 = 37+37(37+1)/2 = 740
• 10 years agoHelpfull: Yes(59) No(1)
• Ans is 740 total applicants...
  37 accepted, 703 rejected.
• 10 years agoHelpfull: Yes(2) No(4)