a % of a)+ (b % of b)=2 % of ab, then what percentage of a is b

• ans=100%
  ((a/100)*a)+((b/100)*b)=((2/100)ab)
  (a^2)/100+(b^2)/100=2ab/100
  (a-b)^2=0
  a=b
  so a is 100% of b.
• 11 years agoHelpfull: Yes(29) No(0)
• a*a/100+b*b/100=ab*2/100 => a=b => a*(100b/a)%=b
  therefore the ans is 100b/a
• 11 years agoHelpfull: Yes(3) No(0)
• ans is a=100% of b
• 11 years agoHelpfull: Yes(2) No(0)
• a2+b2=2ab
  so, a-b=0
  a=b so,ans. is b/a=1*100=100%
• 11 years agoHelpfull: Yes(1) No(0)
• a=b,
  ax=100b => x= 100%.
• 11 years agoHelpfull: Yes(1) No(1)
• srry by mistake....
• 11 years agoHelpfull: Yes(0) No(1)
• 100% is answer
• 11 years agoHelpfull: Yes(0) No(0)
• 100 %
  
  a*a/100 + b*b/100 = 2*ab /100
  
  a^2+b^2=2ab
  a^2 + b^2 -2ab=0
  (a - b)^2 =0
  a-b=0
  a is 100% of b
• 11 years agoHelpfull: Yes(0) No(0)
• by solving the above we will get a=b , so a%b of 100%
  
• 11 years agoHelpfull: Yes(0) No(1)
• no 100% is wrong.
  a=b then %age is 0% ((a-b)/a)*100=((a-a)/a)*100=0*100=0%
• 11 years agoHelpfull: Yes(0) No(1)
• a% of a=a^2/100
  b% of b=b^2/100
  2% of ab=2ab/100
  solving these we get (a-b)^2=0
  so a=b
  therefore a is 100% of b
  so answer is 100%.
• 11 years agoHelpfull: Yes(0) No(0)
• (a-b)^2=0
  a=b
  100%
• 7 years agoHelpfull: Yes(0) No(0)
• 100%
  (a^2 + b^2)/100=(2*a*b)/100
  or, a^2 + b^2=2*a*b
  or, (a-b)^2=0
  or, a=b
• 6 years agoHelpfull: Yes(0) No(0)