A bag contains 2/3 of blue ball and remaining as black ball.In that 4/5th of blue ball and 3/7 of the black ball are defective. If 470 balls of the bag are non defective then how many balls are there in the bag?

• 1/5*2/3*x+4/7*1/3*x=470
  Aftr solving
  We get
  x=1452
• 11 years agoHelpfull: Yes(40) No(1)
• non defective = (1-((2/3 * 4/5 )+(1/3 *4/7)))x
  470=(1-((2/3 * 4/5 )+(1/3 *4/7)))x
  x=1451.47
  x=1451
• 11 years agoHelpfull: Yes(6) No(3)
• 2/3rd of the bag are blue balls.remaining 1/3rd are black. In which 4/5th of blue are defective and 3/7th of black are defective.Given 470 are non-defective balls.
  470=x(2/3)(4/5)+x(1/3)(3/7)
  470=x(8/15+1/7)
  x=695
  ANS:-695
  
• 11 years agoHelpfull: Yes(5) No(16)
• ANS: 1451.470588
  the ratio of black ball : blue ball is 2:1
  let's consider black ball : blue ball = 70:35
  and thus finding corresponding values of non defective balls 34 and then finding the the value of total balls corresponding to 105 balls
• 11 years agoHelpfull: Yes(3) No(2)
• answer is 964.........
• 11 years agoHelpfull: Yes(1) No(7)
• 1451ANS=1/5*2/3*x+4/7*1/3*x=470
• 11 years agoHelpfull: Yes(1) No(1)
• (2/3)**x+(x/3)-(8/15)*x-(3/21)*x=470
  So, after solving x=1451.
• 11 years agoHelpfull: Yes(1) No(2)