A rectangle has twice the area of a square. The length of the rectangle is 14 cm greater than that side of the square whereas breadth is equal to side of the square. Find the perimeter of the square?
(a) 42 cms (b) 14 cms (c) 56 cms (d) 28 cms

• let side of square be x.
  then for rectangle l=14+x and b=x.
  its given
  area of rect=2(area of sq)
  l*b=2(x*x)
  (x+14)*x=2*x^2
  x^2+14x=2x^2
  x^2=14x
  x=14.
  perimeter of sq=4*x=56
• 10 years agoHelpfull: Yes(15) No(0)
• Ans:56 cms (easy one)
• 10 years agoHelpfull: Yes(3) No(3)
• (len*bre)=a^2 l=a+14 b=a
  ((a+14)*a)=a^2.. solve this equation we get the a as 14
  a=14 l=28 b=14 l*b=28*14=392 a^2=14^2=196
  392/192=2 ansis 56 perimeter =4a a*14=56.
• 10 years agoHelpfull: Yes(1) No(1)
• l=14+a;// length of rec equal to 14 gr than side of sq
  b=a;// breadth equal to side of sq
  lb=2a^2;//rect are = twice area of square
  so 14a+a^2=2a^2 ; a^2=14a ; a cancels so a=14 ; perimeter of sq = 4a =4*14=56
• 10 years agoHelpfull: Yes(1) No(0)
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• 9 years agoHelpfull: Yes(0) No(5)
• Let side of square be x.
  Then for rectangle length = 14 + x and breadth = x.
  It is given
  Area of rectangle = 2 × (area of square)
  length × breadth = 2(x × x)
  (x + 14) × x = 2 × x2
  x2 + 14x = 2x2
  x2 = 14x
  x = 14.
  Perimeter of square = 4 × x = 56
• 4 years agoHelpfull: Yes(0) No(0)