A 10-litre mixture of milk and water contains 30 percent water. Two litres of this mixture is taken away.
How many litres of water should now be added so that the amount of milk in the mixture is double that of water?
(a) 1.4 (b) 0.8 (c) 0.4 (d) 0.7

• the answer is option c i.e. 0.4 lit . amount of milk in 8 lit of mix = (8*70)/100 = 5.6 lit. amount of water in 8 lit of mix = 8 - 5.6 = 2.4 lit. half of milk i.e half of 5.6 = 2.8 lit. we need (2.8 - 2.4) lit water more = 0.4 lit
• 11 years agoHelpfull: Yes(23) No(5)
• Ans : C. 0.4L
  In case of a mixture,for any amount of the sample will contain the ingredients in the same proportion.So even if 2 L is taken away,the remaining 8 L will have 30% water and 70% milk.
  Amount of water = 30*8/100 = 2.4L
  Amount of milk = 8-2.4 =5.6L
  For the mixture to have the amount of water double the amount of milk,
  by changing only the amount of water,it shoul d contain 5.6/2 = 2.8L of water.
  Therefore,the amount of water to be added = 2.8 - 2.4 = 0.4L
• 11 years agoHelpfull: Yes(12) No(1)
• 10-2=8 in 8 lit milk (8*.3=2.4)water is contain and (8*.7=5.6)
  if we mix .4 lit of water in the mixture , milk wil be twice the water in mixture
• 11 years agoHelpfull: Yes(4) No(4)
• Ans: (c)0.4
• 11 years agoHelpfull: Yes(3) No(3)
• 10L mixture - 3L of water because(30%)
  8 L mixture - ?
  =2.4 L of water.
  amount of milk is 8 - 2.4 = 5.6 L.
  amout of water must be double that of milk Therefore 5.6/2=2.8
  To get 2.8L from 2.4L we have to add 0.4L
• 7 years agoHelpfull: Yes(1) No(0)
• 10 lt of mixture --> 30% water + 70% milk
  10lt - 2 lt =8lt --> 30%water + 70% milk
  xlt of water is added to the solution so that the ratio of milk and water is 1:2
  8lt + xlt(water) ---> 1:2(water : milk)
  ------consider only water percentage ---
  30%(8lt) + xlt = 1/3(8lt +x)
  solve the above eq
  36 + 15x = 40 +5x
  x=10/4
  x=0.4
• 6 years agoHelpfull: Yes(0) No(0)