There are 4 boxes colored red yellow green and blue if two boxes are selected how many combination are there for at least one green box or one red box to be selected ?

• no of possible combinations are-
  ans=5
  for atleast 1 green box-> (g,y)(g,b)(g,r)=3
  for atleast 1 red box-> (r,y)(r,b)(r,g)=3
  (r,g) is common b/w them so
  n(gUr)= 3 + 3 - 1 = 5
• 11 years agoHelpfull: Yes(31) No(0)
• ans is 5 as all combination minus no reqrd combintn gives solutn..
  4C2-2C2 = 6-1= 5
• 11 years agoHelpfull: Yes(9) No(0)
• The combinations are (R,G), (R,B),(R,Y),(G,B),(G,Y) therefore total 5 combinations hoinga...
• 11 years agoHelpfull: Yes(3) No(0)
• RY,RB,RG,GY,GB THRFOR THE possibl outcome is 5. and anthr way 4C2-2C2=6-1=5
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• RY RG RB GY GB
  so the possible combination is 5.....
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• possible outcome is 5...........
• 11 years agoHelpfull: Yes(1) No(1)
• total no of boxes=5
  r or g=4c2-1
  =5
• 11 years agoHelpfull: Yes(0) No(0)
• Given four colored boxes Red,Yellow,Green and blue
  no of combinations with atleast one Green box or one red box
  green red,green yellow,green blue,red yellow,red blue.
  therefore,Total possible combinations are 5.
  
• 11 years agoHelpfull: Yes(0) No(0)
• Combination of greenred,greenyellow,greenblue,redyellow,redblue.so, Ans is 5.
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