The number of real values of x satisfying the equation log4 (x – 4)2 + log8 (28 – 6x)3 = 1 is

(1) three. (2) two. (3) one. (4) zero.

• log (a)+log b =1
  log a*b=1
  log 4(x-4)^2*8*(28-6x)^3=1
  12 log expresiion=1
  12 (expression) = 10 (raise to 10 on both sides)
  ==> 32(x-4)(28-6x)=10
  now solve for x
• 10 years agoHelpfull: Yes(0) No(0)
• 0 is the ans
  
• 10 years agoHelpfull: Yes(0) No(0)