A is 20 percent more efficient than B. If the two person can complete a piece of work in 60 days.in how many days. A working alone can complete the work

• 110 days
  let one day work of B be x units then one day work of A = 1.2x units
  30x+(1.2x*30)=1
  ie. x=1/132, therefore B takes 132 days alone to complete and A takes 132/1.2=110days
  
• 11 years agoHelpfull: Yes(21) No(8)
• 108 DAYS
  IF b TAKES X DAYS , a TAKES 4X/5 DAYS
  1/X + 5/4X=1/60.....(WORK DONE IN ONE DAY)
  GET X=135,
  4X/5=108....
• 11 years agoHelpfull: Yes(17) No(5)
• but am getting 132 if it solved this way!! please correct this!!
  as effeciencies are 1.2 : 1 = A :B.
  so,
  1/x+1/1.2x=1/60
  => x=110days.
  
  as we need A's work 1/110*1.2 = 132 .
  therefore answer is 132 days!!
• 11 years agoHelpfull: Yes(15) No(9)
• A do 6 units then b do 5 units. in 60 days they do 11*60 =660
  now a do alone in = 660/6
  answer is 110days
• 11 years agoHelpfull: Yes(11) No(2)
• A=1.20B,
  A+B = 1/60,
  A+A/1.20=1/60=>A=1/110,
  s0, PUTTING VALUE B=1/132,
  THEREFORE A CAN DO IN 110 DAYS AND B IN 132 DAYS.
• 11 years agoHelpfull: Yes(7) No(0)
• 132 i the correct answer.
• 11 years agoHelpfull: Yes(4) No(2)
• 132 is not possible at all...A is more efficient than B so it has to be less than double of 120, so 110 is right answer...:)
• 11 years agoHelpfull: Yes(2) No(0)
• will it be 110 or 132.. plz do tell..
• 11 years agoHelpfull: Yes(1) No(0)