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What is the value of the expression % # % (6) + # % # (6)Where % means DOUBLING and # means RECIPROCAL
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- ans is 19/6
- 13 years agoHelpfull: Yes(10) No(0)
- %#%(6)=%#(2*6)=%(1/12)=2*(1/12)=1/6
#%#(6)=#%(1/6)=#2*(1/6)=#1/3=1/(1/3)=3
%#%(6)+#%#(6)=1/6+3=19/6 - 13 years agoHelpfull: Yes(5) No(0)
- hey if u hive ans of the Q
then please explain the logic u use behind it - 13 years agoHelpfull: Yes(1) No(0)
- 2*(1/2*6)+(6/2)=19/6
- 13 years agoHelpfull: Yes(1) No(0)
- 9 is the answer
- 13 years agoHelpfull: Yes(0) No(5)
- Ronak can u explain how u solve this Q
convert the signs int * and / - 13 years agoHelpfull: Yes(0) No(0)
- % means double so double of (6) is 12 then # means reciprocal so 112 then again doubling 1/6.. like wise solve the whole part
1/6+3= 19/6. - 13 years agoHelpfull: Yes(0) No(0)
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