y 2-y 1 -y 2-y 2

question ye tha:-
(y^2+y-6)/(-y^2-y+2)
11 years agoHelpfull: Yes(1) No(0)
if question is: (y^2-y+1)/(-y^2-y+2)>0....then

=> -(y-2)(y+3)/(y+2)(y-1)>0
using wavy curve method(see http://kushagrabasti.blogspot.in/),
y belongs to (1,2)U(-3,2)
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ohh sorry sorry hmm glt type ho gya shiladitya is correct...
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Hello evryone those who wrote elitmus on this sunday please post the question so that other can get benifit
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What is the answer of this question?
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i think question was (y^2-y+1)/(-y^2-y+2) >0 then for what values this equation satisfies?if anyone know what will be the answer of this question then must reply
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I think answer is:
d : y
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answer is : y
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please anyone explain what is correct answer
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If the question was (y^2+y-6)/(-y^2-y+2) >0
then we have (y+3)(y-2)/(y+2)(1-y) >0
which means y lies b/w -3 to -2 or 1 to 2

but if question was
(y^2-y+1)/(-y^2-y+2) >0
then in it for any value of y we have (y^2-y+1)>=1 >0 so concentrate on (-y^2-y+2) we get -2
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(y^2-y+1)/(-y^2-y+2)