SSC
Government Jobs Exams
Numerical Ability
Time Distance and Speed
A man driving at
3/4 th of his original
speed reaches his destination 20 minutes
later than the usual time. Then the usual
time is
Read Solution (Total 1)
-
- Let T be his usual speed,
T=dist/speed
speed=3/4(speed)
According to the given terms,
T=T+20,
Dist/speed= T+20
Dist/(3/4)*speed=T+20
4/3*(Dist/speed)=T+20
4/3*T=T+20 [since T=dist/speed]
4T=3T+60
4T-3T = 60
T=60
So,his usual speed is 60 mins - 5 years agoHelpfull: Yes(0) No(0)
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