three man walk around a cirlce of 1750 metres circumference at the rate of 160 m,120 m,105 m per minute respectively..if thet all start together and walk in same direction when they will be together again for the first time??

• given speeds in meters/min so covert them to m/s
  so, 160/60,120/60,105/60=8/3,2,7/4
  they meet together again for first time =lcm(8/3,2,7/4)=lcm(8,2,7)/hcf(3,1,4)=56/1
  ans:56sec
• 11 years agoHelpfull: Yes(29) No(13)
• 350 meters.
• 11 years agoHelpfull: Yes(11) No(8)
• Time taken by a,b and c to complete one round respectively are 175/16,175/12,1750/105 min. Now taking the lcm of these three time give us the time at which they all meet for the first time lcm(175,175,1750)/hcf(16,12,105)=1750 minutes or 10500seconds or you can also find out the distance using the above time.
• 11 years agoHelpfull: Yes(9) No(0)
• For these ques we find out the relative time of all runners w.r.t fastest runner and then take the LCM of all these times to get the time at which they all meet at first time
  so T(AB)=1750/40=175/4 and T(AC)=1750/55=350/11
  LCM of T(AB) & T(AC)= LCM(175 ,350)/HCF(4,11)= 350/1=350 min (ANS)
  
  PS-10500 is correct ans when they meet at starting point for first time not when they meet first time
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• pls solution in details
• 11 years agoHelpfull: Yes(2) No(4)
• 160/60 , 120/60 , 105/60 = 8/3,2,7/4
  choose one person as contant....and calculate relative speed....1750/(8/3-2) and 1750/(8/3-7/4)...we get 2625 and 2100/11.....lcm(2625,2100/11)= answr is 10500 secnds
• 11 years agoHelpfull: Yes(2) No(0)
• after 32mins.. take their lcm and divide by 105 because it is slowest.. and answer will come 32mins..
• 11 years agoHelpfull: Yes(1) No(2)
• at 141 m?
• 11 years agoHelpfull: Yes(0) No(4)
• They will meet in (175/12) or 14.583 minutes or at 2333.33 metres
• 11 years agoHelpfull: Yes(0) No(3)