In a drawer of shirts, 8 r blue, 6 r green, and 4 r magenta. If Mason draws 2 shirts at random,
what is the probability that at least one of the shirts he draws will be blue?
(A) 25/153
(B) 28/153
(C) 5/17
(D) 4/9
(E) 12/17

• (8C2+8C1X10C1)/18C2=12/17
  So answer is (E)
• 14 years agoHelpfull: Yes(2) No(3)
• At Least Two Means Either One (OR)2..So First Take 1...=> One From Blue And Remaining One From Green Or Magneta=>(8c1*6c1/18c2)+(8c1*4c1/18c2...Now Both R Blue =>8c2/18c2 So Total Is Least One+Both=>12/17
• 12 years agoHelpfull: Yes(1) No(0)
• (E) 12/17
• 14 years agoHelpfull: Yes(0) No(3)
• 12/17
• 14 years agoHelpfull: Yes(0) No(3)
• (8C2+8C1X10C1)/(18C2)=46/153
• 14 years agoHelpfull: Yes(0) No(3)