SSC Government Jobs Exams Numerical Ability Profit and Loss

By selling an article for Rs. 21, a man lost such that the percentage loss was equal to the cost price. The cost priceof the article was

Read Solution (Total 2)

Let CP = x
Loss percentage = (CP-SP)X 100/CP
= (x-21)X100/x
Since loss percentage is equal to CP
(x-21)X100/x = x
100x-2100 = x2
x2-100x+2100 = 0
x ={ -(-100) ± √[(-100)2 – 4X 2100]}/2
=(100 ± √1600)/2
= (100+40)/2 or (100-40)/2
x =70 or 30
8 years agoHelpfull: Yes(0) No(1)

As CP and loss percentage is same.
According to SP= CP× loss percentage, CP and Loss needs to be multiplied. So short trick will be need to check multiple of 21. 30 and 70 will fulfill this criteria.
Either 30 can be CP and 30% loss will be there, so loss multiplier will be 70/100
I.e. 30*70/100= 21 which is SP

Or
70 is CP and 70% is loss so loss multiplier will be 30/100 which results into
70*30/100= 21

This method will help to calculate faster and you will not waste time on quadratic equation calculation.
6 years agoHelpfull: Yes(0) No(0)

SSC Other Question

A sells an article to B at a gain of 25% B sells it to C at a gain of 20% and C sells it to D at a gain of 10%. If D pays Rs. 330 for it, how much did it cost to A ? Half of 100 articles were sold at a profit of 20% and the rest at a profit of 40%. If all the articles had been sold at a profit of 25%, the total profit would have been Rs. 100 less than earlier profit. The cost price of each article was