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9. How many different triangles with a perimeter of 15 cm can be constructed that have integral measurement of sides?
Read Solution (Total 12)
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- Ans : 7
1,7,7; 2,6,7; 3,6,6; 3,5,7; 4,5,6; 4,4,7; 5,5,5.
There are 7 possible triangles. - 11 years agoHelpfull: Yes(19) No(7)
- let the perimeter be p.
no.of triangles if the odd numbered perimeter is given is p=2n-3.(where n is no.of triangles)
no.of triangles if the even numbered perimeter is given is p=2n.
given p=15cm.
hence 15=2n-3
n=9
- 11 years agoHelpfull: Yes(17) No(3)
- We have to find all choices of positive
integers x, y, and z such that
x + y + z = 15
x + y + z = 15
x + y > z
x + z > y
y + z > x
From
x + y + z = 15
x + y = 15 - z
and since x + y > z,
15 - z > z
15 > 2z
7.5 > z
From
x + y + z = 15
x + z = 15 - y
and since x + z > y,
15 - y > y
15 > 2y
7.5 > y
From
x + y + z = 15
y + z = 15 - x
and since y + z > x,
15 - x > x
15 > 2x
7.5 > x
So all the sides are 7 or less
And since to make sure they are non-congruent,
we'll require that x < y < z, so
x = 1 y = 7 z = 7
x = 2 y = 6 z = 7
x = 3 y = 5 z = 7
x = 3 y = 6 z = 6
x = 4 y = 4 z = 7
x = 4 y = 5 z = 6
x = 5 y = 5 z = 5
So there are 7.
- 11 years agoHelpfull: Yes(8) No(3)
- ans : 8
177,267,366,357,456,447,555,573 - 11 years agoHelpfull: Yes(4) No(14)
- ans is 19
(1,1,13)(1,2,12)(1,3,11)(1,4,10)(1,5,9)(1,6,8)(1,7,7)(2,2,11)(2,3,10)(2,4,9)(2,5,8)(2,6,7)(3,3,9)(3,4,8)(3,5,7)(3,6,6)(4,4,7)(4,5,6)(5,5,5) - 11 years agoHelpfull: Yes(3) No(20)
- 14C2...AS Positive integral solution is given by (n-1)C(k-1)
- 11 years agoHelpfull: Yes(2) No(4)
- conditions are (1)a+b+c=15 & (2)summation of any two side > 3rd side
so the combinations are: (1,7,7)(2,6,7)(3,5,7)&(4,4,7)
therefore no of differnt triangles = 4 - 11 years agoHelpfull: Yes(2) No(4)
- Ans.7
771,627,555,564,573,636,645 - 11 years agoHelpfull: Yes(1) No(1)
- soorryy...ans will be 7
- 11 years agoHelpfull: Yes(1) No(2)
- ans 9.
(177),(267),(366),(357),(456),(447),(555),(573),(483).
all possible triangles - 11 years agoHelpfull: Yes(1) No(4)
- Sum of two sides should be greater than three sides. So, total number of triangles possible are 7
1,7,7; 2,6,7; 3,6,6; 3,5,7; 4,5,6; 4,4,7; 5,5,5. - 11 years agoHelpfull: Yes(1) No(0)
- perimeter of 15, the longest side must be 5, 6 or 7. If it is 5 then the middle side can be 5; if it is 6 then the middle side can be 5 or 6; if it is 7 then the middle side can be 4, 5, 6 or 7. Adding those up gives 1+2+4 = 7.
- 11 years agoHelpfull: Yes(0) No(3)
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