two vessels contain spirit and water mixed respectively in the ratio of 1:3 and 3:5 . find the ratio in which these are to be mixed to get a new mixture in which the ratio of spirit to water is 1:2.

• Let Cost Price(CP) of 1 litre spirit be Rs.1
  
  Quantity of spirit in 1 litre mixture from vessel A = 1/4
  
  Cost Price(CP) of 1 litre mixture from vessel A = Rs. 1/4
  
  Quantity of spirit in 1 litre mixture from vessel B = 3/8
  
  Cost Price(CP) of 1 litre mixture from vessel B = Rs. 3/8
  
  Quantity of spirit to be obtained in 1 litre mixture from vessel C = 1/3
  
  Cost Price(CP) of 1 litre mixture from vessel C = Rs. 1/3 = Mean Price
  
  By the rule of alligation, we can write as
  CP of 1 litre mixture from vessel A CP of 1 litre mixture from vessel B
  1/4 3/8
  
  Mean Price
  1/3
  1/3 - 3/8 = - 1/24 1/4 - 1/3 = -1/12
  
  => Mixture from Vessel A : Mixture from Vessel B = - 1/24 : - 1/12 = 1 : 2 = Required Ratio
• 11 years agoHelpfull: Yes(8) No(3)
• x/4+3y/8=1/2(x+y)
  x/y=1/2.
• 7 years agoHelpfull: Yes(0) No(1)
• vessel 1 water=1/4
  vessel 2 water=3/8
  in new mixture water =1/3
  
  1/4 3/8
  
  1/3
  
  
  (3/8-1/3) : (1/3-1/4)
  (9-8)/24:(4-3)/12
  1/24:1/12
  1/2:1
  1:2
• 5 years agoHelpfull: Yes(0) No(0)