A beaker contains 180 lts of wine. Each day 60lts of wine is replaced with same amount of water what is the amount of wine after 3 days?

• ans is 160/3 bcoz this questn is directly solve with the formulae
  wine left= total wine*(1-capacity of wine withdrawn/total wine)^n
  wine left=180*(1-60/180)^3
  =160/3
• 10 years agoHelpfull: Yes(48) No(1)
• (2/3)^3 * 180 = 53.33
• 10 years agoHelpfull: Yes(5) No(0)
• It will be 53.33 after replacing 60 ltr of wine with water on first day the remaining liquid will contain a mixture of 60 lt water and 120 lts of wine, that is 2/3 rd of original concentration. as it is not possible to separate wine the same 60 ltr of mixture will be replaced making it again 2/3rd of previous concentration and the same continuous so it will be (2/3*2/3*2/3)*180= 53.33
• 10 years agoHelpfull: Yes(5) No(0)
• simple formula
  [1-y/x]^n
  where x=initial amount=180
  y=amount taken=60
  n=no.of repetitions=3
  after substitution we get ans 160/3
• 10 years agoHelpfull: Yes(4) No(5)
• can u guys please explain the formula ... i mean can u elaborate how that formula is derived
• 10 years agoHelpfull: Yes(4) No(1)
• 180*(1-60/180)^3 = 160/3
• 10 years agoHelpfull: Yes(3) No(0)
• 29.62 % pure wine !
• 10 years agoHelpfull: Yes(1) No(2)
• Initially, wine=180
  Taking out 60 from the beaker and adding 60 water:
  wine=180-60=120, water=60
  Ratio of wine:water=120/180:60/180=2/3:1/3=2:1
  Again taking out 60 from the beaker and adding 60 water:
  wine=120-(2/3*60)=80, water=60-(1/3*60)+60=100
  Ratio of wine:water=80/180:100/180=4:5
  Again taking out 60 from the beaker and adding 60 water:
  wine=80-(4/9*60)=160/3, water=100-(5/9*60)+60=380/3
• 9 years agoHelpfull: Yes(1) No(0)
• 53.33 liters of the wine will remain !!!
• 10 years agoHelpfull: Yes(0) No(0)