if 3 dices are rolled simultaneously then find probability that sum is 10?

• 1/8
  as 10 can be obtained as (1,6,3)->6 ways;(1,4,5)->6 ways;(2,4,4)->3 ways;
  (2,6,2)->3 ways;(2,5,3)->6 ways;(3,3,4)->3 ways.
  total ways=27
  probability=27/216=1/8
• 11 years agoHelpfull: Yes(19) No(2)
• Possible ways :-
  (6,3,1) - 6
  (6,2,2) - 3
  (5,3,2) - 6
  (5,4,1) - 6
  (4,4,2) - 3
  (4,5,1) - 6
  (4,3,3) - 3
  Total no of possibilites = 33
  probability = 33/216 = 11/72
• 11 years agoHelpfull: Yes(8) No(15)
• Ans : 0.125
  The different combinations of 1,3,6; 1,4,5; 2,2,6; 2,3,5; 2,4,4; 3,3,4 can produce the sum 10.For each of these there can be further arrangements within 3 dices.so 3P3 + 3P3 + 3P3/2! + 3P3 + 3P3/2! + 3P3/2! = 3*6 + 3*3 = 27
  Total possible outcomes in the dice = 6^3 = 216
  Therefore the required probability = 27/216 = 1/8 = 0.125
• 11 years agoHelpfull: Yes(6) No(0)
• three dices s0 6^3=216
  from the three dices we are getting 27 numbers sum of 10
  s0 ans will be
  27/216
• 11 years agoHelpfull: Yes(1) No(0)
• if two dices are rolled then
  p=3/36=1/12.
  but if 3 dices are rolled then
  n(s)=6*6*6;
  n(a)={}
  p(A)=n(a)/n(s)
  pls solve anyone n(a) and put value in this
  
• 11 years agoHelpfull: Yes(0) No(2)
• 1/18?
  
  as 10 can be obtained with dice giving 1,5,4(6 ways) ad 2,5,3(6 ways)
  so 12/216 i.e 1/18
• 11 years agoHelpfull: Yes(0) No(4)
• CASES :-
  (6,3,1) - 6
  (6,2,2) - 3
  (5,3,2) - 6
  (5,4,1) - 6
  (4,4,2) - 3
  (4,3,3) - 3
  Total no of possibilites = 27
  probability = 27/216.
• 11 years agoHelpfull: Yes(0) No(0)
• @ Debabrata Roy Chowdhury
  ur process is right but u forgot to alter the last letter in ur ans, bcz u calculated EIRNGO as the 45th term not as 46th. so ans will be EIRNOG
• 11 years agoHelpfull: Yes(0) No(0)
• Possible ways :-
  (6,3,1) - 6
  (6,2,2) - 3
  (5,3,2) - 6
  (5,4,1) - 6
  (4,4,2) - 3
  (4,3,3) - 3
  Total no of possibilites = 27
  probability = 27/216 = 1/8;
  
  
• 10 years agoHelpfull: Yes(0) No(0)