n where n 4 k gives number of trailing zeros if n

@prayas: yaar its simple you have to find the number of zeros in the n!.as n>4 so take 5 n divide it by 5 u get number of zero equal to 1.rule z divide the given number by 5 until you get 1 atlast..for example if you have to find number of zeros in 100! den divide 100 by 5 you get 20 as quotient now divide 20 by 5 you get 4 bt further u cant divide it by 5..so total number of zeros equal to 20+4=24..u have to take only integer value of quotient.if u do above process u got to knw that for n is less than 200 it z not psble to have 5,11,17,23,29,30,36,42 number of zeros...because 20! divide by 5 gives number of zeros 4 nd 25 ! divide by 5 gives number of zeros 6....by above ruledivide till u get 1..after 4 u directly get number of zeros 6 so 5 zeros not possible...n it z rule to find number of zeros u have to divide the number by 5..:)
11 years agoHelpfull: Yes(4) No(0)

if n is less than 200 then how many values k can not take from 1 to 47.
solution...8 values k can not take these are 5,11,17,23,29,30,36,42.. it means these number of zeros not psble in factorial n which are less than 200.
11 years agoHelpfull: Yes(3) No(0)
@gyaneshwari-i only know a way to wind no. of zero by finding no. of 2 & 5...m unable get ur rule...can u explain it once more..thanks
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sry the complete question is if n
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if n
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Will u please elaborate gyaneshvari???
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OK..got it..thankx Gyaneshvari
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if anyone knows what was the answer of geometry question i.e, quadrilateral circumscribes in circle on 13th oct xm
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for calculating number of zeros v have to calculate how many 10's bt 10 z nt prime number so resolve it into 2 nd 5...as 2 vl b available in abundance and 5 in scarcity so 5 is deciding factor...dats y i have only divide the number by 5...i thnk nw it z clear:)
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i got how to find number of zero of nay number but i am not getting how you took this number 5,11,17,23,29,30,36,42?plz anyone explain
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pryas goel plz explain bro i m not getting 25/5=5 how it give 6 same the other value also plz explain
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n! where n>4 , k gives number of trailing zeros.if n