Let n be a natural number then n n n -1 is always divisible by option A 6 B 12

ans is 6 by options
or
n(n*n-1)=n^3-n=(n-1)(n)(n+1)
any 3 consecutive natural numbers product is divisible by 6
11 years agoHelpfull: Yes(7) No(0)
by options it turns out to be 6.
11 years agoHelpfull: Yes(2) No(0)
if is n=2,3,4,.... then 6..
11 years agoHelpfull: Yes(2) No(0)
6 is the answer, as all the other options are multiples of 6, therefore any number divisible by them, is always divisible by 6, and by checking for n, it is true yhat the expression is always divisible by 6.
11 years agoHelpfull: Yes(2) No(0)
(A) 6 is the correct answer
11 years agoHelpfull: Yes(1) No(0)
6....is d ans......
11 years agoHelpfull: Yes(0) No(0)

Let n be a natural number, then n(n*n -1) is always divisible by?
option
(A) 6
(B) 12
(C) 24
(D) 48
(E) None of these