5)One person start from his home towards college which is 53 km far away. Another person
started from college towards home after an hour. the speed of first one is 4kmph and the second
one is 3 kmph. Then, what is the distance from home to their meeting point?
AND:21 km.

6)3 machines can complete the work in 4,5, and 6 hours respectively. due to power failures they
did the work alternatively. Then what is time taken to complete the work?
ANS:9/20
pls help

• Ans is 32 kms from home and 21 kms from college.
  If s is distance from home where they met , then
  s/4 = 1+ (53-s)/3
  solving it, we get s= 32 kms.
  The first person travelled 32 kms in 8 hrs @ 4kmph and
  The 2nd person travelled 21 kms in 7 hrs @ 3kmph.
• 13 years agoHelpfull: Yes(22) No(1)
• total distance=53km,late meeting point from home=x,then remaining distance=53-x.
  here given in question another person started from college after an hour, so one hour more then first person have to go. so T1=T2+1.
  T1=X/4
  T2=((53-X)/3)+1
  T1=T2+1(time taken by both person for miiting must be equal)
  x/4=(53-x)3+1
  x/4=56-x/3
  7x=224
  x=32
  then they will meet at 53-x or 53-32km it mean 21km from home
• 13 years agoHelpfull: Yes(11) No(6)
• 3 machines can complete the work in 4,5, and 6 hours respectively. due to power failures they did the work alternatively.
  Work done in 1st hr = 15/60
  Work done in 2nd hr = 12/60
  
  Work done in 3rd hr = 10/60
  
  Work done in 4th hr = 15/60
  Balance work = 1-(15+12+10+15)/60 =1-52/60 = 8/60
  Time taken for 8/60 work by 2nd machine = (8/60)*(60/12)=8/12 hrs = 2/3 hrs =40 mins
  so total time taken = 4 hrs 40 mins
  
  
• 13 years agoHelpfull: Yes(10) No(7)
• Ans is 32 kms from home and 21 kms from college.
  If s is distance from home where they met , then
  s/4 = 1+ (53-s)/4
  solving it, we get s= 32 kms.
  The first person travelled 32 kms in 8 hrs @ 4kmph and
  The 2nd person travelled 21 kms in 7 hrs @ 3kmph.
• 13 years agoHelpfull: Yes(4) No(0)
• 5) after 1hr B started so A covers 4km
  so distance have to cover by A and B is (53-4) = 49 km only
  and every hr both cover (3+4) = 7km so after 7 hr they meet each other
  
  now the distance from home to their meeting point = (7*4)km + remaining 4km = 32km
  
• 8 years agoHelpfull: Yes(1) No(0)
• In first three hours, work done=(1/4)+(1/5)+(1/6)=37/60
  remaining work=1-(37/60)=23/60
  on the next fourth hour=1/4
  now the remaining work will be=4/15
  time is taken by the second machine=1/(1/5) * (4/15)
  Hence total time=5 hour 20 min
  
• 8 years agoHelpfull: Yes(0) No(0)