20 men can do a piece of work in 30 days. After how many days should 5 men leave so that the work is completed in 35days?

• Ans. 15 days
  20 men can do the work in 30 days..
  Therefore 20 men in x days can do x/30 part of the work..
  lly 15 men in 35-x days can do (35-x)/40 portion of the work..
  x/30 + (35-x)/40 = 1
  x = 15
• 11 years agoHelpfull: Yes(17) No(5)
• ans is 15 days.........
  20 men can do a piece of work in 1 day is 1/30...
  1 men can do 1/600 in 1 day....
  after x days 5 men leaves the work then 15 men can do 1/40 of the work in 1 day....
  in x days 20 men can do x/30 of the total work.....
  then the remaining work is 1-x/30=(30-x)/30....
  15 men can do 1/40 of the work in 1 day then (30-x)/30 th work can do in (35-x) days ....
  by solving these 2 equations we get x=15 days .....
  after 15 days 5 men can leave the work
• 11 years agoHelpfull: Yes(13) No(1)
• ans- let in 'x' days 5 men will leave.
  20 men do one work in 30 days.
  20 men will do 1/30 work in 1 day.
  20 men will do x/30 work in x days.
  1 man will do 1/600 work in 1 day.
  1 man will do one work in 600 days.
  15 men will do one work in 600/15=40 days.
  15 men in 35-x days will do (35-x)/40 work.
  s0, x/30 + (35-x)/40 =1
  => x=15 days
  answer is 15 days.
• 11 years agoHelpfull: Yes(12) No(0)
• 20 men 1 day work work 20M=1/30 so M=1/600
  give when 5 men leaves the work will be completed in 35 days
  so 20 men do the work in for 'x' days let
  then 15 men do the work in '35-x' days
  so (x)20M+(35-x)15M=1(equate to 1 since the work is completed)
  x/30+(35-x)*15/600=1
  x/30+(35-x)/40=1
  by solving x=15 days is the ans
• 11 years agoHelpfull: Yes(10) No(0)
• Answer is 15 days.
  since 20*30=600.
  (15(days)*20(men))+(20(days)*15(men))=600.
  first 15 days 20 men will work and rest of 20 days 15 men will work.
  therefore after 15 days 5 men can leave to complete work in 35 days.
• 11 years agoHelpfull: Yes(3) No(0)
• M1 * D1 = M2 * D2
  20 * 30 = 20 * x + 15 * (35 - x)
  600 = 5x + 525
  x = 15 is Answer
  Right hand side
  20 men can do x days works.
  then 5 men leave
  remaining 15 men can do work remaining (35 - x) days which is 15 * (35 - x)
• 9 years agoHelpfull: Yes(1) No(0)
• Ans. 25 days
  20 men can do the work in 30 days..
  Therefore 20 men in x days can do x/30 part of the work..
  lly 15 men in 35-x days can do (35-x)/60 portion of the work..
  x/30 + (35-x)/60 = 1
  x = 25
• 11 years agoHelpfull: Yes(0) No(11)
• (20*n) + 15 * (35-n) = 600
  n=15
  So 15 days after 5 men leaves
• 9 years agoHelpfull: Yes(0) No(0)