Consider a sequence 1,2,2,3,3,3,4,4,4,4,1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4,4,4,.....
Then what is the number at 2320th position in the sequence?
a) 2
b) 1
c) 3
d) 4

• IN each repeatition elements containing 10,20,30,..
  let 2320th element containing in Nth repeatition ,
  10(1+2+3+...+Nth)>=2320
  10N(N+1)/2>=2320
  so,at N=21, no. of elements=2310
  hence, in 22th rept..from 2311th upto 2332th elements will be 1.........
  ANS..(b)..[1]
• 10 years agoHelpfull: Yes(2) No(2)