A cow & Horse are bought for Rs.2000. The cow is sold at a profit of 20% and the Horse is sold at a loss of 10%. The overall gain is Rs.40. The cost price of the cow is :
a) 700
b) 800
c) 1200
d) 1300

• let c.p of cow=x, therefore c.p of horse= 2000-x
  acc to problem S.P of cow = 6x/5 nd S.P of horse=9(2000-x)/10
  ass overall gain is 40, therefore total S.P-total C.P=40
  {6x/5+9(2000-x)/10}-2000=40 solving equation,
  we get x=800, therefore C.P of Cow= 800(ans)
• 11 years agoHelpfull: Yes(4) No(0)
• b) 800
  Cow=x, horse=2000-x
• 11 years agoHelpfull: Yes(0) No(2)
• 6/5........9/10....in which denominatr represent cp and numerator sp
  didd od denominatr(10-5) =5,these 5 points means rs 40
  5 =40
  100=40/5*100
  ie 800.....
• 11 years agoHelpfull: Yes(0) No(0)
• cost price of cow=X
  so,cost price of horse=(2000-X)
  for cow,
  profit%=(profit*100)/cost price
  profit=20X/100
  for horse
  loss=10(2000-X)/100
  a/c question,
  20X/100-{10(2000-X)}/100=40
  so X=800
  cost price of cow=800
• 10 years agoHelpfull: Yes(0) No(0)
• Anyone answe dis ques plz-a certain sum of noney trebles itself in 8 yrs.in hw many yrs it will be 5 times?
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