23456789101112.... . 4481 Find the remainder when divided by 45.

• if question is 1234.....4481 then solution will be this
  prime factorisation of 45 is 3*3*5
  ie.e number should be multiple of 9 and 5
  for this 1234...4481 can be written as
  (124567....4400+81)
  Since last two digits are zero it is divisible by 5 and since sum of digits is 990 so it is also divisible by 9
  Now the rest part is 81
  when we divide 81 by 45 it will give the remainder as 36
  ans is 36
  
• 10 years agoHelpfull: Yes(27) No(11)
• take it sm=(1+2+3+4+5+6+7+8+9+10+...+4481)-1
  sm=(4481*4480)/2-1=10037439
  now sm%45=9
  so reminder=9
• 10 years agoHelpfull: Yes(1) No(0)
• 81-45=36 :p
• 10 years agoHelpfull: Yes(0) No(1)