TCS
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Numerical Ability
LCM and HCF
If the lcm of 2 natural no.s A nd B is 1260, what is the minimum possible value of A+B?
option
a) 71
b) 73
c) 72
d) 70
Read Solution (Total 9)
-
- Factors of 1260 are 2,2,3,3,7,5
Now minimum possible two numbers A and B formed from these factors are
7*5=35=A
2*2*3*3=36=B
so minimum value of A+B is 71 - 11 years agoHelpfull: Yes(33) No(0)
- on what basis divided as 7*5 and 2*2*3*3 ??
- 11 years agoHelpfull: Yes(4) No(1)
- Answer is 71
and the two numbers are 35 and 36 whose Lcm is 1260 - 11 years agoHelpfull: Yes(1) No(2)
- 35*35=1260,
so, a+b = 71; - 11 years agoHelpfull: Yes(1) No(3)
- 72
lcm is 6*6*7*5
6*7 + 6*5
42 + 30
72
- 11 years agoHelpfull: Yes(0) No(4)
- 1260 => 2*2*3*3*5*7
1260 => 35 *36
so, a+b => 35 +36 => 71 Ans. - 11 years agoHelpfull: Yes(0) No(0)
- minimum possible combination we have to choose that's why 2*2*3*3 and 7*5 was taken
if we take 2*2*3 and 3*7*5 then the value will be greater .. - 10 years agoHelpfull: Yes(0) No(0)
- Factors of 1260 are 2*2*3*3*7*5
now co primes nos with product = 1260 from these factors are (4*315),(35*36),(45*28)
since 35+36 = 71 , is the lowest so A is 35 & B is 36 SO ANSWER IS a+b MIN VALUE IS 71 - 6 years agoHelpfull: Yes(0) No(0)
- 7*5+3*3*2*2=71
A+B=72 - 6 years agoHelpfull: Yes(0) No(0)
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