If the lcm of 2 natural no.s A nd B is 1260, what is the minimum possible value of A+B?
option
a) 71
b) 73
c) 72
d) 70

• Factors of 1260 are 2,2,3,3,7,5
  Now minimum possible two numbers A and B formed from these factors are
  7*5=35=A
  2*2*3*3=36=B
  so minimum value of A+B is 71
• 10 years agoHelpfull: Yes(33) No(0)
• on what basis divided as 7*5 and 2*2*3*3 ??
• 10 years agoHelpfull: Yes(4) No(1)
• Answer is 71
  and the two numbers are 35 and 36 whose Lcm is 1260
• 10 years agoHelpfull: Yes(1) No(2)
• 35*35=1260,
  so, a+b = 71;
• 10 years agoHelpfull: Yes(1) No(3)
• 72
  lcm is 6*6*7*5
  6*7 + 6*5
  42 + 30
  72
  
• 10 years agoHelpfull: Yes(0) No(4)
• 1260 => 2*2*3*3*5*7
  
  1260 => 35 *36
  so, a+b => 35 +36 => 71 Ans.
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• minimum possible combination we have to choose that's why 2*2*3*3 and 7*5 was taken
  if we take 2*2*3 and 3*7*5 then the value will be greater ..
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• Factors of 1260 are 2*2*3*3*7*5
  now co primes nos with product = 1260 from these factors are (4*315),(35*36),(45*28)
  
  since 35+36 = 71 , is the lowest so A is 35 & B is 36 SO ANSWER IS a+b MIN VALUE IS 71
• 5 years agoHelpfull: Yes(0) No(0)
• 7*5+3*3*2*2=71
  A+B=72
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