TCS
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Numerical Ability
Probability
One number is picked at random frm the first 1000 natural no.s. It turns out to be a square. What is the probability that it is greater than 500.
option
a) 5/31
b) 6/31
c) 8/31
d) 9/31
Read Solution (Total 12)
-
- 9/31 is the answer
23,24,25,26,27,28,29,30,31 - 10 years agoHelpfull: Yes(58) No(1)
- Square's till 1000 r 1,4,9,16,25,36,49,64,81,100,121,144,169,196,225,256,289,324,361,400,441,484,529,576,625,676,729,784,841,900,961=total of 31 in this above 500 r 9 thus solution is 9/31
- 10 years agoHelpfull: Yes(32) No(0)
- 23,24,25,26,27,28,29,30,31=9 therefore E=9...S=31c1
ans equals to 9/31c1=9/31 ans - 10 years agoHelpfull: Yes(6) No(0)
- 9/31 is correct
- 10 years agoHelpfull: Yes(5) No(2)
- 8/31...........all squares of nos greater than 23 are smaller than 1000 and less than 500(8 such nos)
and a total of 31 nos whoose squares are less than 31
so, the probability is 8/31 - 10 years agoHelpfull: Yes(3) No(15)
- squre number after 500 is 509=23^2,and belove 1000 is 961=31^2........so favourable cases 31-23=8 and total cases 0 to 31 therefore ans is 8/31
- 10 years agoHelpfull: Yes(3) No(7)
- The soln is quite easy:
(1000)^1/2=31.62 & (500)^1/2=22.36 so between 500 to 100 there would 31-22=9 squares and there are a total of 31 squares so the required probability would be 9/31 - 10 years agoHelpfull: Yes(3) No(0)
- 8/31...........all squares of nos greater than 23 are smaller than 1000 and less than 500(8 such nos)
and a total of 31 nos whoose squares are less than 1000
so, the probability is 8/31 - 10 years agoHelpfull: Yes(1) No(11)
- 9/31-23,24,25,26,27,28,29,30,31
- 10 years agoHelpfull: Yes(1) No(0)
- 9/31 is the prob,
Coz the number's whose squares are in (500,1000) are
23,24,25,26,27,28,29,30,31,
So, 9/31. Ans - 10 years agoHelpfull: Yes(1) No(0)
- 9/31 is the answer
23,24,25,26,27,28,29,30,31 - 10 years agoHelpfull: Yes(0) No(0)
- how only 9, because it is given above than 500 but no upper limit is given(1000) is the number
- 9 years agoHelpfull: Yes(0) No(0)
TCS Other Question
# 9
An ant lives on the surface of a regular tetrahedron with edges of length 5cm. It is currently at the midpoint of one of the edges and has to travel to the midpoint of the opposite edge. What is the length (in cm) of the shortest route to the destination assuming the ant can only travel along the surface of the tetrahedron? (Note: 2 edges in a tetrahedron are said to be opposite if they don't share any endpoints).
2.5*√3
2.5*(1 + √3)
7.5
5
2.5*√2
The number 6,12,21,22,27,34 are placed in the boxes a,b,c,d,e,f shows below in a certain order such that the sum of the entries in each of the extreme rows and each of th extreme columns(i.e, top,bottom row,left most column and right most column) are the same number k.what is the value of k?