All the capital letters of the English alphabet from A to Z followed by the lower case letters from A to Z are placed one in each slot, in 52 slots around a circle in clockwise direction. All the slots are counted in the clockwise direction starting with the slot containing A, and the letter in every fifth slot is removed. How many more slots will have letters left in them immediately after M is removed from its slot?
[1] 13
[2] 14
[3] 16
[4] 12

• There will totally be 52 letters out of which ‘m’ is the 39th letter. If we count from ‘A’, in the first round the letters removed will be those positioned in the slots of 5, 10, 15…………. 50 (10 letters) then we have 3, 8, 13…….48(10 letters) then 1, 6, 11…….. 51 (11 letters) then 4, 9, 14…….34 (7 letters) before 39 Total number of letters struck off is 10 + 10 + 11+ 7 = 38 letter before 39, so m is the 39th letter to be removed. So, 13 letters are left in their slots.
• 13 years agoHelpfull: Yes(7) No(2)
• Answer is 13
  
  According to question slots and corresponding alphabets are
  A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26
  a b c d e f g h i j k l m n o p q r s t u v w x y z
  27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52
  
  
  Removing slot numbers until m i.e. slot no 39 is removed
  5
  10
  15
  20
  25
  30
  35
  40
  45
  50
  3
  8
  13
  18
  23
  28
  33
  38
  43
  48
  1
  6
  11
  16
  21
  26
  31
  36
  41
  46
  51
  4
  9
  14
  19
  24
  29
  34
  39
  
  so total 39 alphabets are removed
  
  Remaining alphabets are 52-39=13
  
  hence answer is 13
• 13 years agoHelpfull: Yes(6) No(1)
• its like...
  when we write A-Z in order M holds the 13th position
  hence while place these alphabets as said..
  AaBbCc...Zz M occurs to hold 25th and m holds 26th(i.e 13*2-1 and 13*2)
  As M,m is removed from its slot total number of letters to remain =26
  and as the 5th consecutive alphabet is vacated ,total alphabet remaining=
  26-(5*2)=16
• 13 years agoHelpfull: Yes(2) No(15)
• the total alphabets arranged Aa Bb Cc . . . like this the Mth number is 13*2-1=25
  in every slot has one capital+one small letters.
  so there are only 26 slots filled with letters.26/5 slots removed(remove 3 8 13 18 23)
  so remaining slots 26-(5*2)=16
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
• 13 years agoHelpfull: Yes(2) No(6)
• since m is the 39th slot,elements remain are 13
• 13 years agoHelpfull: Yes(2) No(1)
• when we consider circular arrangement we will get the answer as 8...
  
  because we can remove the 5th elements in the cyclic manner...if after removing M we will have 8 elements remaining...
  
  if we wont consider cyclic the it will be 13 or 7.. but the correct answer for this question is 8
• 13 years agoHelpfull: Yes(1) No(0)
• 
  answer:16
• 13 years agoHelpfull: Yes(0) No(5)
• !!! ans z 13.coz
  every letter z removed after 5 slotts and dare z 52 letters den 10 wil b reduced and for removing 2 more letter we will add 10 slootts more to making 15 means removing d leeter at 13th position too which is M.....
• 13 years agoHelpfull: Yes(0) No(0)
• #2 14
  ok it says that after every 5 letters the fifth one is removed do doin that you would end up with 14 left
• 13 years agoHelpfull: Yes(0) No(0)
• here will totally be 52 letters out of which ‘m’ is the 39th letter. If we count from A, in the first round the letter removed will be those positioned in the slots of.
  5, 10, 15……………………50, 10 letters, then
  3, 8, 13……………………48, 10 letters, then
  1, 6, 11………………………. 51, 11 letters, then
  4, 9, 14, 19, 24, 29, 34 – 7 letters before 39 total number of letter struck off is 10 + 10 +11 + 7 = 38 letters before 39 fi 50, m is the 39th letter to be removed.
  So, 13 letters are left in their slots. Hence the answer is 13.
• 5 Months agoHelpfull: Yes(0) No(0)