A jar has 50 coins: all pennies, nickles, and dimes, with a total value of $3.50. There are twice as many nickles as as pennies. How many are there of each coin?

• p=>pennies
  n=> nickles
  d=> dimes
  A jar has 50 coins,so
  p+n+d=50
  total value is $3.50
  0.01p + 0.05n + 0.10d=3.50
  
  n=2p(given)
  
  p+5n+10d=350
  
  p+10p+10d=350
  
  11p + 10d =350 ......(1)
  
  (now in terms of coin)
  
  p+n+d=50
  p+2p+d=50
  
  3p+d=50 --- ....(2)
  
  after solving we get
  
  p=7.8(ans)
• 11 years agoHelpfull: Yes(13) No(6)
• If we take $3.10 then exact answer is coming, i think problem in question!
  Penny= 1cent
  Nickle= 5cent
  Dime= 10cent
  
  So equation in terms of $ will be:
  0.01p + 0.05n + 0.10d=3.10
  or
  p+5n+10d=310
  (Given n=2p)
  So, 11p+10d=310....eqn1
  
  We know, p+n+d=50
  then
  3p+d=50....eqn2
  
  Solving eqn1 &2
  we get;
  p=10
  d=20
  n=20
  
  10p= 10cents
  20nickle= 100cents
  20dimes= 200cents
  
  So value comes out to be: 310 cents i.e. $3.10
  
  
  
• 11 years agoHelpfull: Yes(12) No(0)
• 0.01p + 0.05n + 0.10d=3.50
  From where are you getting this?
• 11 years agoHelpfull: Yes(8) No(0)
• value of dime can't b determined so not possible
• 11 years agoHelpfull: Yes(5) No(1)
• Is 1 Pennies=$.01
  1 nickles=$.05
  1 dimes=$.10 ?????
• 11 years agoHelpfull: Yes(2) No(0)
• plz explain how do v get
  0.01p + 0.05n + 0.10d=3.50????
• 11 years agoHelpfull: Yes(2) No(0)
• p=pennies .01 .01p
  2p=nickles .05 .05(2p)
  d=dimes .10 .10(50-3p)=5-.30p
  
  p+2p+d=50
  d=50-3p
  .01p+.05(2p)+5-.3p=3.5
  .01p+.1p+5-.3p=3.5
  -.19p+5=3.5
  5-3.5=.19p
  1.5=.19p
  
• 11 years agoHelpfull: Yes(0) No(0)