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A team consists of both boys and girls along with a coach. After a game, the coach drinks 9 litres of water, a boy drinks 7 litres of water and a girl drinks 4 litres of water. If after a game 42 litres of water was consumed, find the number of boys in the team.
option
(A) 5 boys
(B) 4 boys
(C) 3 boys
(D) 2 boys
Read Solution (Total 13)
-
- 3 boys
9+ 7x + 4y = 42
x,y are number of boys and girls
7x+4y = 33
the only integers which satisfies this equation are x=3 y=3 - 11 years agoHelpfull: Yes(61) No(0)
- 3 boys...
3*7+3*4+1*9=42 - 11 years agoHelpfull: Yes(4) No(0)
- 42 litre.coach drink 9 litre remaining 33 litre.If 3 boys means 3*7=21 litres... so remaining 12 litres for 3 girls...
so answer is 3 boys
- 11 years agoHelpfull: Yes(1) No(0)
- do verfication
- 11 years agoHelpfull: Yes(1) No(0)
- the answer is 3 because total useage water is 42 we can substract 9 (coach) then remaining is 33 if each boy drinks 7lit means 7*3=21 then we have 12lit of water it can use by 3 of girls so ans is 3 boys
- 11 years agoHelpfull: Yes(1) No(0)
- 42=4x+7y+9*1
so by random visualisation 42=3*4+3*7+1*9
so 3 boys and 3 girls and a coach!!!simple - 10 years agoHelpfull: Yes(1) No(0)
- Ans:
3
3 boys-3*4=12
1coach=9
3girls-3*7=21 - 10 years agoHelpfull: Yes(0) No(0)
- 3 boys
3 girls
1 coach - 10 years agoHelpfull: Yes(0) No(0)
- 9 ltr by coach...so remaining water=32
so,
7x+4y=32
this equation can hv many sltns bt chkng options....
5-rejected(bcz 7*5>32)
3-(7*3=21,remaining 11-not possible bcz 11 is not multiple of 4)
2-(7*2=14,remaining 18- not possible bcz 11 is not multiple of 4)
4-(7*4=28,remaining 4-1 girl,satisfied)
so ans is 4 boys and 1 girl :) - 10 years agoHelpfull: Yes(0) No(3)
- 9*coach+7*boys+4*girls=42 litres
if boys=3
9*1+7*3+4*3=42litres - 10 years agoHelpfull: Yes(0) No(0)
- 3 is the answer
coach=42-9=33
boys=33-7*3=12
girls=4*3=12 - 10 years agoHelpfull: Yes(0) No(0)
- difference is 120-10=110
- 10 years agoHelpfull: Yes(0) No(0)
- Coach =1********>9
3Boys=7*3=21
3girls=4*3=12
Total=42
So 3Boys only - 9 years agoHelpfull: Yes(0) No(0)
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