TCS
Company
Numerical Ability
Arithmetic
Let A be a 2-digit number and B be another 2-digit number formed by reversing the digits of A. If A + B + (products of digits of the number A) = 145, then what is the sum of the digits of A?
Read Solution (Total 5)
-
- It will be 11(x+y)+xy=145
145=11*13+2
for xy=2; x,y must be 1 and 2 which doesn't solve
145=11*12+13
for xy=13: x,y must be 1 and 13 which doesn't solve
145=11*11+24
for xy=24: x,y may be 3,8 or 6,4
since 3+8 is 11 hence number must be 83 or 38
sum=11 - 11 years agoHelpfull: Yes(16) No(1)
- 10x+y+10y+x+xy=145......we will get...A=83...ans = 11
- 11 years agoHelpfull: Yes(7) No(17)
- hit nd trial...
- 11 years agoHelpfull: Yes(4) No(0)
- how do u get A=83?
- 11 years agoHelpfull: Yes(3) No(1)
- plzzzzzzzzz tel options deblina
- 11 years agoHelpfull: Yes(2) No(0)
TCS Other Question
Seven speakers A1, A2, A3,……, A7 were scheduled to speak at a function. In how many ways their speech can be arranged, such that:
A1 speaks before A3 , and
A3 speaks before A5 .
7,9,17,42,173,298