A school has 120, 192 and 144 students enrolled for its science, arts and commerce courses. All students have to be seated in rooms for an exam such that each room has students of only the same course and also all rooms have equal number of students. What is the least number of rooms needed?

• sorry we have to take hcf which is 24
  total no of rooms = 120/24+192/24+144/24=19
• 11 years agoHelpfull: Yes(36) No(0)
• We have to find the maximum number which divides all the given numbers so that number of roots get minimized.
  HCF of 120,192 & 144 is 24.
  Each room have 24 students of the same course.
  Then rooms needed (120/24)+(192/24)+(144/24) = 5 +8 + 6 = 19
• 11 years agoHelpfull: Yes(10) No(0)
• I think we should take lcm of 120,192,144 which is 2880
• 11 years agoHelpfull: Yes(1) No(16)
• HCF of 120,192,144 is 24 so number of rooms required is (120/24)+(192/24)+(144/24)
  which is equal to 19
• 11 years agoHelpfull: Yes(1) No(0)
• hcf is 24
  total no of rooms = 120/24+192/24+144/24=19
  
• 11 years agoHelpfull: Yes(1) No(0)