1234...............4465 when divided by 45(series is upto the natural no. 4465)

• answer is 10...
  see 1234....4465 is completely divisible by 5
  now we need to check it by 9
  n(n+1)/2=4465*4466/2
  =9970345
  9970345%9=1
  
  so 10 is the no which is completely divisible by 5 and give 1 remainder when divided by 9..
• 11 years agoHelpfull: Yes(19) No(9)
• 20 am i right???
• 11 years agoHelpfull: Yes(9) No(11)
• series is upto 4465
  lets calculate sum upto 4465= 4465*4466/2...by n(n+1)/2
  now divide the above expression by 45
  i.e. 4465*4466/(2*45)
  now 4465 is 99*45
  and also 4466 is divided by 2
  so,remainder is 0
• 11 years agoHelpfull: Yes(1) No(8)