a=2, b=3, c=6 Find the value of c/(a+b)-(a+b)/c

• c/(a+b)-(a+b)/c
  = (c/(a+b))-((a+b)/c)
  = (6/(2+3))-((2+3)/6)
  = (6/5)-(5/6)
  = 11/30
• 10 years agoHelpfull: Yes(24) No(4)
• i guess 11/30 is solution
• 10 years agoHelpfull: Yes(3) No(1)
• 11/30 is the solution.
• 10 years agoHelpfull: Yes(3) No(0)
• (6/5) - (5/6) = 11/36
• 10 years agoHelpfull: Yes(2) No(15)
• c/(a+b)-(a+b)/c
  6/(2+3)-(2+3)/6
  6/5-5/6
  1-0
  1
• 10 years agoHelpfull: Yes(2) No(12)
• it will be according to bodmass
  1st we hav 2 simplify bracket then division then sub
  so 1st take (a+b) = 5
  so, 6/5-5/6 = 1.2-0.8333=.367
• 10 years agoHelpfull: Yes(2) No(2)
• c/(a+b)-(a+b)/c
  =c^2/((c-1)(a+b))
  =36/5*5
  =36/25
• 10 years agoHelpfull: Yes(1) No(4)
• .4 is correct ans
• 10 years agoHelpfull: Yes(1) No(1)
• the answer is 1/6 because () takes first priority in solving.after this have to take lcm and difference the values
• 10 years agoHelpfull: Yes(0) No(2)
• using bodmas open the brackets a+b=5
  c/5-5/c
  =6/5-5/6 =1.2-0.6 =0.6
• 10 years agoHelpfull: Yes(0) No(3)
• it is 11/30
• 9 years agoHelpfull: Yes(0) No(0)