A schoolyard contains only bicycles and 4 wheeled wagons. On Tuesday, the total number of wheels in the schoolyard was 134. What could be possible number of bicycles?
(a) 16
(b) 15
(c) 18
(d) 14

• 15
  b'coz 134-15*2=104 which is divisible by 4.
  and no other option fullfill this condition
• 13 years agoHelpfull: Yes(31) No(2)
• let no of bicycles=x and wagon=y
  so,
  2x+4y=134
  => x+2y=67
  as x and y should be integer.
  x=odd no.
  hence 15 ans.
• 13 years agoHelpfull: Yes(14) No(4)
• first choose option and multiply it by 2(number of tyre of bycycle) then subtract it from 134.If remainder is divisible by 4 then your option is right.
• 13 years agoHelpfull: Yes(9) No(1)
• we can easily predict from answer...
  as if we take 15 bicyles then we have 30 bicycles wheels and rest is 104 which is divisible by 4 .
  hence ans is b)15
• 13 years agoHelpfull: Yes(3) No(2)
• the total no. of wheels are 134 divide it by 4 we get 33 with remainder 2
  its means 33 wagons and 2 bicycles . if we reduced 1 wagon thn we ill get 2 more cycles thus decrease in this manner u will get ans= 16
• 13 years agoHelpfull: Yes(2) No(9)
• ans is 15.............
  
• 13 years agoHelpfull: Yes(2) No(3)
• Ans...(b)15
  Reason............
  BY hit & trail method,
  134=26*(4)+15*(2)
  only satisfies the total no of wheels.
• 9 years agoHelpfull: Yes(1) No(1)
• ans:15
  no of bicycle wheels 15*2=30 and wagons wheels=total wheels-bicycle wheels
  i.e 134-30=104 and no 4 wheel wagons = 104/4=26.
  remaining all option come on decimal values.
• 11 years agoHelpfull: Yes(0) No(2)
• let x be the bicycles
  y be the wagons
  2x+4y=134
  x+2y=67
• 5 years agoHelpfull: Yes(0) No(1)
• Ans : (b) 15
  As
  No of wheels for 16 cycles = 16 x 2 = 32
  So no of wheels for wagons = 134 - 32 = 102
  Which is not Possible as 102 is not divisible by 4
  
  Similarly for case of 18 and 14.
  
  But for 15 cycles we have 30 wheels thus making the no of wheels for wagons as 104
  which is possible with total no of wagons as 26 (104/4)
• 3 years agoHelpfull: Yes(0) No(0)