A man whose age is 45 yrs has 3 sons named John,jill,jack. He went to a park weekly twice.he loves his sons very much. On a certain day he find # shopkippers sailing different things. An apple cost 1penny, 2chocalate costs 1penny.& 3 bananas cost 1 penny. He has bought equal no. of apple, chocolate & banana for each son. If the total amount he invest is 7 penny then how many he has bought from each piece for his son?

a)1app,1cho,1 banana

b)1 app,2cho,3 banana

c)1app,2cho,1banana

• cost for 1 apple=1 penny
  cost for 1 chocolate=1/2 penny
  cost for 1 banana=1/3 penny
  now go to options,
  3*[1*(1)+1*(1/2)+1*(1/3)]=11/2
  3*[1*(1)+2*(1/2)+3*(1/3)]=9
  3*[1*(1)+2*(1/2)+1*(1/3)]=7
  so, option c is correct.
  
• 13 years agoHelpfull: Yes(39) No(0)
• ans is 1 app,2cho,1banana
  
  3 members are there.....3 app cost is 3peny
  6 cho cost is 3peny
  3 banana cost is 1 peny
  total 7 penny.
• 13 years agoHelpfull: Yes(10) No(2)
• 1app,2cho,1banana
• 13 years agoHelpfull: Yes(3) No(0)
• he bought 3 apples for 3 penny, 6 chocolate for 3 penny and
  3 bananas for 1 penny.... totally 7 penny... and each child
  will have one apple two chocolates and one banana
• 10 years agoHelpfull: Yes(0) No(0)
• we can go through ... option so we can do in less time
  so for option 3,
  cost of 1 app=1
  cost of 2 cho=1
  cost of 1 banana= 1/3
  so ,cost of 1app,2cho,1 banana=1+1+1/3;
  he has 3 son and he spended 7 penny
  so 3*(1+1+1/3)=7
  answer c
• 7 years agoHelpfull: Yes(0) No(0)