In one of the mathematics books, the pages were numbered incorrectly. The page number on the nth page was f(n) where:
f(1) = 8
f(2*n) = f(n)
f(2*n+1) = f(n) + f(n+1)
What was the page number on 13th page?
13
40
32
55
8

• f(13)=f(2*6+1).here n value is 6,so f(6)+f(6+1)=f(6)+f(7).
  now we need to find values of f(6) and f(7)
  f(6)=f(2*3)=f(3).
  now find f(7)=f(2*3+1)=f(3)+f(3+1)=f(3)+f(4).
  find values of f(3),f(3) and f(4)..
  f(3)=f(2*1+1)=f(1)+f(1+1)=f(1)+f(2)..
  we have f(1)=8 given.so we need to find still f(2)
  f(2)=f(2*1)=f(1)=8
  therefore value of f(3)=f(1)+f(2)=8+8=16..
  now find value of f(4)=f(2*2)=f(2)=8(already calculated above)
  Finally we have f(3)+f(3)+f(4)=16+16+8=40
  so ans is 40........
• 10 years agoHelpfull: Yes(18) No(0)
• ans z 40..by putting the values..
  
• 10 years agoHelpfull: Yes(13) No(3)
• 32....yr by puttng d values in d eqn...
• 10 years agoHelpfull: Yes(3) No(18)
• its 30 not 42
• 10 years agoHelpfull: Yes(0) No(0)