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dhiman is trying to hone his skills on counting and comes across the following problem.
How many 4 digit numbers are divisible by 5 with all the digits distinct? In the options below, n! = 12...n is the factorial function (e.g. 4! = 24).
His answer would be :
189!/7!
9!/6!
88!/6!
168!/6!
17*8!/6!

Read Solution (Total 2)

ans should be D..
suppose 0 is at unit place. then, numbers can be formed as- 9*8*7*1
if we say 5 is at unit place, then numbers can be formed as- 8*8*7*1
so, total cases is sum of these.
case I can b written as- 9!/6!=9*(8!/6!) and case II can be written as 8*(8!/6!)
taking common out- (9+8)8!/6! = 17(8!/6!)
11 years agoHelpfull: Yes(86) No(1)

9*8*7*1 + 8*8*7*1

= 17(8!/6!)
11 years agoHelpfull: Yes(2) No(1)

TCS Other Question

Your friend prakhar has a collection of 13 bags containing cricket balls to be distributed among some bowlers. The bags are labeled "bag_1", "bag_2", ..., "bag_13" and the bag labeled "bag_n" contains exactly n cricket balls. The bags are sealed and cannot be opened prior to distribution. What is the maximum number of bowlers that prakhar can distribute the bags to if each bowler gets the same number of balls?

a. 7
b. 13
c. 8
d. 5
e. 6 8 people (including brajesh) go for a picnic. At the end of the day, they all line up for a photograph. In how many ways can they line up if brajesh's friend rajendra wants to stand next to brajesh. In the options below, n! = 1*2*...*n is the factorial function (e.g. 4! = 24).
7!
6! + 2
8!
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2*(6!)