a^h232 find a value of h that makes it divisible by 7.....a=7^3-5

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• 10 years agoHelpfull: Yes(21) No(3)
• a=7^3-5=7^-2
  
  (7^-2) % 7 != 0 but
  ((7^-2)^-1) % 7 = 0
  so at least we need -1 (a -ve no.) as a power of 7^-2 to make it divisible by 0
  .....that means h232 must be less than zero..thats the only condition...
  s0 h can be any < 0...now check your options...if h=-1 given then choose it..otherwise any negative will satisfy
• 10 years agoHelpfull: Yes(7) No(20)
• a=7^3-5
  a=7^-2
  a=1/14
  if a^-1 then a is divisible by 7
  any thing to the power multiple of -1 is divisible
  hence h=-1
• 10 years agoHelpfull: Yes(3) No(9)